Linear A, the script of Bronze Age Crete, has puzzled researchers for over a century.
Today, we’re releasing the code and data behind Plasma researcher @IdaeanDaktyl’s proposed decipherment. Explore the evidence and test the readings.
plasma.ai/research/linear-a
Alongside names, we also analyzed the most common words.
Nearly 9 in 10 of Linear A’s roughly 1,600 inscriptions are administrative in nature, recorded by scribes of the time to keep track of goods and people.
Notably, we see the word for "queen" on 20 tablets and "king" on 6.
Two prayer phrases, "I make myself a dwelling" and "sacred song," occur repeatedly on stone vessels left on mountaintops.
Every reading includes sources and a confidence tier.
Explore the evidence, test the readings, and tell us where they fail: plasma.ai/research/linear-a
Erdős #940: Which integers can you build by adding numbers whose prime factors all occur with high exponents?
Call a number “r-powerful” if every prime in its factorization has exponent at least r. For example, 16 = 2⁴ and 2,592 = 2⁵ × 3⁴ are both 4-powerful. In 1976, Erdős asked whether infinitely many integers cannot be written as a sum of at most r r-powerful numbers, for each r ≥ 3.
We proved the r = 4 case, and more: the exceptions occupy a positive proportion of the integers. Even with four summands and every 4-powerful number available, a persistent fraction remains unreachable.
The proof combines restrictions on remainders modulo carefully chosen primes. Each restriction limits how many sums are possible; together, they make representable integers scarce within a chosen arithmetic progression. Making those restrictions work uniformly requires quartic Gauss sums, Hilbert reciprocity, and the Chebotarev density theorem.
We also formalized Beyer de Ryke’s result for r = 3. Both proofs are in Lean. The full conjecture remains open, including whether the representable integers have density zero.
Explore the proofs: erdosproblems.ai/940
Erdős 420, parts 2 and 3: How much does the number of divisors grow when you extend a factorial by just a few terms?
In 1980, Erdős and Graham asked whether the ratio of divisor counts for (n + ⌊log n⌋)! and n! can get arbitrarily close to every number greater than 1.
We proved it can. Pick a target—1.01, π, a million—and any desired accuracy. The ratio comes that close for arbitrarily large n.
The same holds if you replace log n with any nondecreasing function that grows without bound but stays below log n, however slowly it grows.
The proof combines @OpenAI’s recent work on Dirichlet L-functions with Maynard’s sieve. We construct short intervals with carefully placed prime contributions, control the remaining terms, then slide a window across the interval to bring the divisor ratio close to the target.
The result is formalized in Lean. erdosproblems.ai/420
The proof combines @OpenAI’s recent work on Dirichlet L-functions with Maynard’s sieve. We construct short intervals with carefully placed prime contributions, control the remaining terms, then slide a window across the interval to bring the divisor ratio close to the target.
The result is formalized in Lean. erdosproblems.ai/420
Replying to @axiommathai
@axiommathai’s CFSG formalization shows agent swarms can now carry a proof spread across 500 papers and 15,000 pages through the Lean kernel in 24 days.
What excites us most is what gets built on top. Our Erdős 420 proof already stands on their PrimeGapsLib formalization of Maynard’s sieve, extended by our own agents. Libraries like these help people and agents build on each other’s work to advance research.
See our proof and explore more Erdős problems: erdosproblems.ai/420
Plasma AI retweeted
Incredibly proud of Plasma researcher @IdaeanDaktyl and his proposed decipherment of Linear A, the script of Bronze Age Crete.
Today we’re releasing the code and data behind his research so others can explore, test and build on it.
Linear A, the script of Bronze Age Crete, has puzzled researchers for over a century.
Today, we’re releasing the code and data behind Plasma researcher @IdaeanDaktyl’s proposed decipherment. Explore the evidence and test the readings.
plasma.ai/research/linear-a
We invite scholars, independent researchers and anyone curious about the ancient world to explore the material, contribute sources, and pursue their own readings.
github.com/plasma-ai/kaphtor
On Monday we shared our proof of Erdős #111, posed by Erdős, Hajnal, and Szemerédi in 1979. Here’s more about what the result means and how the proof works.
Start with a graph that cannot be properly colored even with a countably infinite list of colors: 1, 2, 3, ... For each n, let h(n) be the worst-case number of edges you must delete from an n-vertex piece to make it two-colorable, as shown in the video.
We proved h(n)/n → ∞. Pick any deletion budget per vertex: a hundred, a million. For every sufficiently large n, there is an n-vertex piece that exceeds it.
The core theorem runs in the opposite direction: if every finite piece can be made two-colorable by deleting at most C edges per vertex, for one fixed C, then the entire graph can be colored with countably many colors.
To prove this, we build random red/blue labels through successive layers of the graph. The labels need not form a proper coloring. Instead, we control how often adjacent vertices receive matching labels.
We then treat the random labels as vectors in a Hilbert space. Their geometry lets us partition the vertices into countably many classes. Within each class, every vertex has only finitely many neighbors in earlier layers, allowing us to assemble a proper coloring.
One final step turns this theorem into the full limit. We find disjoint finite pieces that each require many deletions per vertex, then pack copies of the same size into larger pieces. That carries the lower bound to every sufficiently large n.
The proof is public and formalized in Lean: erdosproblems.ai/111
Yesterday we shared our proof of Erdős #173, a geometry conjecture dating to 1973. The video shows the puzzle: color every point of the plane red or blue, and try to avoid a triangle of a chosen shape and size with all three corners the same color.
You can avoid equilateral triangles of one particular size. But then equilateral triangles of every other size must appear with all three corners the same color. So must copies of every non-equilateral triangle, with exactly the prescribed shape and size.
The surprising step in the proof: a question about triangles becomes a question about pairs. With two colors, three corners have either three matching pairs or exactly one. So knowing how often pairs match tells us how often all three corners match.
This lets us adapt @OpenAI’s recent methods, combine them with a geometric reduction from 1975, and finish with analysis.
The proof is public and formalized in Lean: erdosproblems.ai/173



