Mospact21 (@mospact21) profile picture

Mospact21

@mospact21
Joined July 2023
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Replying to @memcculloch
Mike, I think I have derived particle radius from Energy using QI. r= √(ħ/(2π√(πE)) Proton=0.878fm Electron=5.753fm I also have a related formula for Planck Length from cosmic E Lp=√(ħ/√(πE)) Values seem to work, Feedback appreciated.
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nitter.cf/i/status/2047686814807… @memcculloch If you missed it, this was the motivation for the formula. Maybe my rationale is incorrect but the idea of the particle as an anti-information void I think fits well with QI substitutions and the idea of local Planck conditions.
Mospact21 (@mospact21) profile pictureMospact21@mospact21Apr 24
Replying to @mospact21 @memcculloch
@memcculloch My assumption wasn't that the electron was bouncing between the plates. My hunch was that the particle size is set by the cosmic radius. Smaller d fools the electron into a tighter loop. Then the electron rediscovers the cosmic radius, expands deleting information.
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nitter.cf/i/status/2046087483717… @Franck_McBecker did you see this? I have reason to think the theoretical thrust might be half of the predicted here but broadly this formula has no area or voltage. Does this map with your experience?
Mospact21 (@mospact21) profile pictureMospact21@mospact21Apr 20
Replying to @memcculloch
Derivation for you to ponder. E=kTN =ħad/2πcLp Δp=ħ/2d v=Δp/m_e =ħ/2m_ed Since ħ/m_e=cλ̄꜀ v=cλ̄꜀/2d a=v²/d =(cλ̄꜀/2d)²/d =c²λ̄꜀²/4d³ E=(ħd/2πcLp)(c²λ̄꜀²/4d³) =ħcλ̄꜀²/8πd²Lp Power=(I/e)E =ħIcλ̄꜀²/8πed²Lp Force=P/c  F=ħIλ̄꜀²/8πed²Lp F=2.4x10-⁷(I/d²)
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